PHP code help

[tertius]

I use:
$today = date("F - j - Y");

however I want to add a certain number of days to it.
Like: $nextweek = 7

How can I add those 7 days to the current date? and still keep it in the same format.

[stevon]

Originally Posted by tertius

I use:
$today = date("F - j - Y");

however I want to add a certain number of days to it.
Like: $nextweek = 7

How can I add those 7 days to the current date? and still keep it in the same format.

this function u can use with MySQL database

function dt_only_date_minus_x_days( $x ) {
  return date("Y-m-d", time( ) - ( $x * 24 * 60 * 60 ) );
}

function dt_minus_x_days( $x ) {
  return date("Y-m-d G:i:s", time( ) - ( $x * 24 * 60 * 60 ) );
}

function dt_now( ) {
  return dt_minus_x_days( 0 );
}

function dt_yesterday( ) {
  return dt_minus_x_days( 1 );
}

[stargate]

Try his one

$time = time() + (7 * 24 * 60 * 60);
print $today = date("F - j - Y");              # today
print $today = date("F - j - Y", $time);    # next week

[Axe Solutions]

I think this will be useful for u

date("F - j - Y", strtotime('+1 week'));